Re: Operators

• Date: Thu, 11 Apr 1996 21:26:52 PDT
• From:
  Jefferson.M.Dubrule@dartmouth.edu (Jefferson M. Dubrule)
• Reply-To:
  manta@dartmouth.edu (manta)

--- "Matthew `GrendelFish' Dockrey" wrote:
And ((x && !y) || (!x && y)) is fairly clunky.
--- end of quoted material ---
Sorry to reply twice, but here's a slightly more elegant, slightly less obvious
way:
((!!x + !!y) == 1)

-manta

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